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Riddle me this
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RPGDot Forums > Absolutely Off Topic

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Hexy
High Emperor
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Joined: 28 Jun 2002
Posts: 621
   

Yes, an arrow is correct!
Post Sat Mar 19, 2005 4:46 am
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titus
Survivor of Hell
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Joined: 03 Aug 2003
Posts: 778
Location: Standing at the Hell mouth
   

try this one:
you have a bottle of 5 litres anda bottle of 3 litres.
Fill the bottle of 5 litres with exactly 2 litres
go ahead have fun
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Post Sun Mar 20, 2005 8:57 pm
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Hexy
High Emperor
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Joined: 28 Jun 2002
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Fill the 5 litre bottle, then use that bottle to fill the 3 litre one. Then you'll have two litres.

Here's one:
Slowest when fat, quickest when thin
Wind is the bane to the gift that it brings
Post Mon Mar 21, 2005 8:06 am
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titus
Survivor of Hell
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oops Did I say fill it with 2 litres exactly? I meant 4 :$
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Post Mon Mar 21, 2005 6:41 pm
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titus
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a cloud?
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Post Mon Mar 21, 2005 6:42 pm
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Graham 2
High Emperor
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Joined: 29 Jan 2004
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Location: Preston/England
   

quote:
Originally posted by titus
oops Did I say fill it with 2 litres exactly? I meant 4 :$


That's from Die hard

If you fill 3 litres up to the top then pour it into the 5 litre bottle then fill the 3 litre bottle up again and pour what you can into the 5 litre bottle then your left with 1 litre in the 3 litre bottle, empty the 5 litre bottle and pour the contents of the 3 litre bottle into the 5 liter bottle, then simply fill up the 3 litre bottle again and pour that into the 5 litre bottle and hey presto 4 litres
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Post Mon Mar 21, 2005 7:13 pm
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titus
Survivor of Hell
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Joined: 03 Aug 2003
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Location: Standing at the Hell mouth
   

you are right it is from Die hard and I asked that one because I always forget the solution
Was I right about the cloud?
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Post Mon Mar 21, 2005 7:39 pm
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Val
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Location: Utah, USA
   

I think it's a candle.
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Post Wed Mar 23, 2005 8:17 pm
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Hexy
High Emperor
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Yes, a candle.
Post Thu Mar 24, 2005 6:17 am
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tolgerias
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Joined: 15 Jul 2004
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Location: The Netherlands
   

@ hexy One of the BG2 spellhold riddles I think
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Post Thu Mar 24, 2005 7:32 am
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VPeric
Most Exalted Highlord
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Joined: 13 Jul 2003
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Location: Serbia
   

Well, I'd feel bad about ripping off Tolkien, or some game, so I'll go for a bit of a math problem:

A man goes to the countryside, and sees a farm with a lot of children outside. He asks one of the boys how much brothers and sisters he has, and he answers: "I've got as much brothers, as sisters". Then the man asks a girl the same question and she says: "I've got twice as much brothers as I do sisters". How many boys and girls are there?

(btw, sorry for the poor wording. I'm not a native speaker and I had to translate. )
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Post Thu Mar 24, 2005 1:14 pm
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titus
Survivor of Hell
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Boys = 4 girls = 3
but I am not 100% sure about it
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Post Thu Mar 24, 2005 1:44 pm
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Arma
Mysterious Lady
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Joined: 24 Oct 2003
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I think that there are 4 boys and 3 girls, since a boy (of the 4 brothers) would have
quote:
as many brothers as sisters
i.e - 3, and a girl (of the 3 sisters) would have
quote:
twice as many brothers as sisters
ie. 2x2=4.
Post Thu Mar 24, 2005 2:10 pm
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VPeric
Most Exalted Highlord
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Joined: 13 Jul 2003
Posts: 418
Location: Serbia
   

Yes, you are correct. Well done! Lets try again... I hope you understand what I mean:

You have 6 metal balls, all but one the same weight, and a way to, err.. measure them (It's the thing where you can put something on one side, and something else on the other, and it shows if the two sides are equal, or if one weights more than the other. Hope that makes sense. Oh, and I'd really appreciate it if you could tell me what it's called. ). Anyway, how do you find the odd ball, that hasn't got the same weight, in 3 measurements?
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Post Thu Mar 24, 2005 2:17 pm
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Darrius Cole
Most Exalted Highlord
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Joined: 04 May 2004
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Measurement 1. Begin by weighing 4 balls, two on each side.
If the scale is balanced:
-You can eliminate all four balls on the scale they are equal.
Measurement 2 & 3. Measure the remaining two balls on at a time against only one of the first for balls. You are looking for the ball that imbalances the scale.

If the scale is unbalanced:
-You can eliminate the two balls you did not measure, they are equal.
-Remove one ball from each side and place it in front of the plate you took it off of.
Measurement 2. Measure the two balls left on the scale.
If the scale is now balanced you know that the balls you removed created the imbalance.
Measurement 3. Measure any one of the balls under the plates against any one of the balls left on the scale. If the new ball creates an imbalance it is the one you are looking for. If the scale is still balanced the other ball is the one your are looking for.

If the scale is still imbalanced, you know that the two balls you removed are also balanced and the one of the balls on the scale created the imbalance. Mark one of the balls on the scale 'A' and mark the other 'B'
Measurement 3. Measure one of the balls you know is equal against either A or B. If the scale is imbalanced you know the marked ball still on the scale is the uneven one. If the scale is imbalanced you know the marked ball not on the scale is the uneven one.


VPeric or anyone else, I am curious to know how you would have done it?
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Post Thu Mar 24, 2005 6:51 pm
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