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Very Hard Riddles
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RPGDot Forums > Absolutely Off Topic

Do you enjoy riddles?
No!
100%
 100%  [ 5 ]
Total Votes : 5

Author Thread
Lintra
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Joined: 23 Apr 2002
Posts: 9448
Location: Bermuda, the triangle place with SANDY BEACHES
   

quote:
Originally posted by Michael C
The No Vacancy problem: If the hotel must serve an infinite number of forrest people they will never have time to serve you, so my guess is that you can't get a room!


I went looking back over old posts trying not to duplicate, but I thought a new riddle would be fun.

Good answer on the Tractor Beam. Must be correct (drove the Tractor over the ice).

No Vacancy: I was going to bring this one up, but you beat me to it... my logic is as follows:

Z = Set of *all* integers is infinite and people are discrete units, and therefore integer like (it is refered to as countably infinite) since you are just another integer, there is a room for you. Mapping is as follows:

f = set of all forest people. f(i) = forest person i, zero indexed. Lim as i -> inf = Z

g = set of all forset people + you where g(0) = you and g(1) = f(0).
lim as i -> inf g = Z therfore there exists a room for you.

for the next problem (no vacancies)

Q = Set of *all* rational numbers if q in Q then q = a/b where a,b in Z and b <> 0. Q is also countably infinite, but Z in Q & Q not in Z and Q is infinite, in fact there are Z Z's in Q since
1, 1 + 1/2, 1+1/3...1+1/z is in Q,
2, 2 + 1/2, 2+1/3...2+1/z is in Q,
.
.
.
z, z + 1/2, z + 1/3...z+1/z is in Q,

so there is room for many infinities in this hotel!


Last edited by Lintra on Mon May 13, 2002 7:03 pm; edited 1 time in total
Post Mon May 13, 2002 4:51 pm
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Lintra
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Location: Bermuda, the triangle place with SANDY BEACHES
   

I forgot to point this out...

There is problem with adding an additional point to an infinity. Here it is:

Make the following construct:
a circle "C" with its south pole touching (tangent to) the real line "R" at 0.
Then draw a line from the N pole through the circle through the line.

This assigns 1 point on R for each point in C. It is a one to one correspondence...except for the north pole. A line just through the north pole (tangent) is parellel to R. Where do tangent lines meet? At infinity.

A layman's description of this is "Drop an extra point into the real line, and it curls up into a circle" or "the circle = the real line + 1 point".

I don't believe it is relevent to the prior discussion, but then I am 20 years out of practice
Post Mon May 13, 2002 6:05 pm
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Lintra
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This riddle is "Three's a Crowd"

"After solving the riddle of the three wise folks, three scoundrels claim to be the smartest in the country. So you decide to give them a challenge. Suspecting that the thing they care about most is money, you give them $100 and tell them they are to divide this money observing the following rule: they are to discuss offers and counter-offers from each other and then take a vote. Majority vote wins.
Sounds easy enough... now the question is, assuming each person is motivated to take the largest amount possible, what will the outcome be?
Note: careful... if the answer were that they split it 50% / 50% / 0%, or 1/3 / 1/3 / 1/3, it wouldn't be a riddle! "

As far as I can see this is what happens:

Remember, the only rule is to increase wealth (you can not voluntarily decrease it).

After one round A+B agree to vote together and split the pot. So round end of round one the amounts are 50-50-0 (A-B-C)

Then a offers to split B’s amount with C if C votes with him, so end of round two the amounts are 75-25-0 (A-C-B)

Then C offers to split the 75 with B, the best a can do is offer to give C’s 25 to B so B takes C’s offer. End of round 3: 63.5-37.5-0 (C-B-A).

Round 4 and later, the one with the second most offers to split the most with the guy with 0. This is an infinite series with an end result 2/3-1/3-0, but no one person gets the 2/3, it is constantly shifting around.

The technical proof is let x_i = max amount in round i
Then in round i the guy with 0 will get x_i/2 leaving the rest for the winner so
x_i = 100 – x_(i-1)

If you extend this you get

x_i = 100(1 – ½ +1/4-1/8+1/6-1/32+...+x_(i – j)/2.

lim as x --> inf of x_i = 100(1 – ½ + 1/4-1/8+1/6-1/32+...)
= 100 (1/2 + 1/8 + 1/32 +...+ (1/2)^(2n+1) + ...
= 100 sum( ½^(2n – 1))
= 100 * ½ * sum( ½^2n)
= 50 * sum (1/4^n)
= 50 * 1/(1-1/4) a general rule (I can prove it if you wish)
= 50 * 4/ 3 = 66.66666

I played a little fast and loose with summation signs and limits, hoping they'd be obvious (this is not a great word processor!).
Post Mon May 13, 2002 7:47 pm
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Potentated Knight of Ni
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I never knew that we had so many smart people on RPGDot (expluding moderators ).

It is not fair that Lintra can solve all of the problems so easily.
--(for he/she is an acutary )
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Post Mon May 13, 2002 9:12 pm
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Michael C
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Joined: 09 Jul 2001
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Location: Aarhus, Denmark
   

Regarding the "No vacancy" riddle. I agree that you through math. can prove that there is a room for you, but the fact that there are an infinite amount of forrest people before you in line, you will never get to the counter and order that room.
Post Tue May 14, 2002 7:10 am
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Michael C
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Location: Aarhus, Denmark
   

Taking the first link (random riddles) from original page. The No.1 riddle where a 40 pounds rock has been broken into 4 uneven pieces which each weight a certain amount, so you can use a scale and messure any amount between 1 and 40 pounds (hole numbers), with only these 4 stones.

I found if the 4 stones weight 1,3,9 and 27 pounds, then it's possible!
Post Tue May 14, 2002 11:53 am
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Michael C
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No.3 riddle on random riddle page: Solution is letter "M". Easy one!
Post Tue May 14, 2002 11:55 am
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Lintra
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quote:
Originally posted by Michael C
Regarding the "No vacancy" riddle. I agree that you through math. can prove that there is a room for you, but the fact that there are an infinite amount of forrest people before you in line, you will never get to the counter and order that room.


I like your approach, it is clean a simple (and I would not have thought of it ). The problem is the riddle. It states

"In the forest, a hotel has an infinite number of rooms. An infinite number of forest people arrive and each takes a room. So far so good. Now you would like a room. "

So each forest person has a room already. The question is if there is a room for you.

Also

M is good

The poundage on the rocks follows the pattern
1,
3 = (1)*2 + 1,
9 = (1+3)*2+1,
27 = (1+3+9)*2+1
81 = (1+3+9+27)*2 + 1
etc

Work was slow yesterday and looks to be slow today. I printed out a list of the riddles what we have not answered yet and am working my way down the list. Would you me to post it?
Post Tue May 14, 2002 12:17 pm
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Lintra
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Joined: 23 Apr 2002
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quote:
Originally posted by Potentated Knight of Ni
...It is not fair that Lintra can solve all of the problems so easily.
--(for he/she is an acutary )


Not as easily as you might think! Michael C got the Eat&Run Riddle, and Yog Sothoth got the three dots
Post Tue May 14, 2002 12:27 pm
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Michael C
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Location: Aarhus, Denmark
   

Lintra: Yep a remaining list of riddles would be fine!

BTW The solution on No.4 riddle in (random riddle) is: "Nothing". Nothing is stronger than god, nothing is more evil than the devil etc.
Post Tue May 14, 2002 12:58 pm
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Michael C
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Location: Aarhus, Denmark
   

Lintra: Your formula used for the 4 rocks is working and probably the most correct one, I just used the simple algorith nx3 to find the next number.
Ex.
1
1x3=3
3x3=9
9x3=27
27x3=81
81x3=243 and so on!
Post Tue May 14, 2002 1:06 pm
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Lintra
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Location: Bermuda, the triangle place with SANDY BEACHES
   

quote:
Originally posted by Michael C
Lintra: Yep a remaining list of riddles would be fine!

BTW The solution on No.4 riddle in (random riddle) is: "Nothing". Nothing is stronger than god, nothing is more evil than the devil etc.


Good ans on nothing, and here is the list- I think it is complete:

Three Dots - Done
Hat-trick - Done
Three's a Crowd - Done
Auction Action - Done
Ties that Bind
Hats Off
Open Door Policy - Done
Trouble in River City - Done
Timing is Everything
Light Bridge - Done
Flight Plight - Infinite series
Lazy Susan
Lying Defeeted - Done
No Vacancy - Done?
No Vacancies - Done?
Apairantly Not
Sailor's Delight
Eat and Run - Done
Tractor Beam - Done
Enlightenment
Ashpynxiated - Done
Heads Up

I had to edit this...while the text entry screen understands tabs they don't show up properly when submitted

PS - I had totally missed that you were using powers of 3! I got there using the combination approach. There is a number theory theorum in there somewhere, but I don't feel up to digging it out
Post Tue May 14, 2002 1:11 pm
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Yog Sothoth
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Joined: 01 May 2002
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quote:
Originally posted by Michael C
Lintra: Your formula used for the 4 rocks is working and probably the most correct one, I just used the simple algorith nx3 to find the next number.
Ex.
1
1x3=3
3x3=9
9x3=27
27x3=81
81x3=243 and so on!


I don't understand what does it mean the "to an accuracy of one pound" in the text of the riddle... how could you measure 7 pounds for example?
(i'm studing hard and i'm "out of work" with my mind... now i understand only the meaning of numbers in civil prodecure code articles... TILT )
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Post Tue May 14, 2002 2:15 pm
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Lintra
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With a simple balance put the 3 lb wgt on one side and the 9 and 1 on the other, the difference is 7 lbs.
Post Tue May 14, 2002 2:34 pm
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Yog Sothoth
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ops! there was a balance too... i never noticed sorry
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Post Tue May 14, 2002 2:36 pm
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