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| Do you enjoy riddles? |
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| Total Votes : 5 |
Lintra
Elf Friend
Joined: 23 Apr 2002
Posts: 9448
Location: Bermuda, the triangle place with SANDY BEACHES |
quote:
Originally posted by Beebelo
For the Barber riddle, the poor looking barber cuts the good looking barber's hair and vice versa, so the poor looking barber is a better barber.
For the Horse/Friday riddle, A man rides to town on Friday, stays 3 days, and leaves on Friday works very easily if the Horse's name is Friday.
I *like* the friday solution! Good one  |
Thu May 23, 2002 11:06 am |
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Michael C
Black Dragon
Joined: 09 Jul 2001
Posts: 1595
Location: Aarhus, Denmark |
Originally posted by Beebelo
For the Barber riddle, the poor looking barber cuts the good looking barber's hair and vice versa, so the poor looking barber is a better barber.
For the Horse/Friday riddle, A man rides to town on Friday, stays 3 days, and leaves on Friday works very easily if the Horse's name is Friday.
I like your barber riddle solution better than mine! 
The horse called Friday must be THE solution! Good work! |
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Thu May 23, 2002 11:52 am |
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Yog Sothoth
The All in One
Joined: 01 May 2002
Posts: 1086
Location: Between Space and Time |
quote:
Originally posted by Beebelo
For the Horse/Friday riddle, A man rides to town on Friday, stays 3 days, and leaves on Friday works very easily if the Horse's name is Friday.
woooo  better solution than mine... 
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Thu May 23, 2002 12:25 pm |
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Maggot
Magister of the Light
Joined: 17 Jul 2001
Posts: 392
Location: Reykjavik, Iceland |
Well, I have been thinking on the Hats Off riddle, and I think the obvious answer is the correct one. 50% is the highest percentage.
Since the guesses must be simultaneous, there is no way for one guess to affect another, via some secret communication.
Since the outcome of one coin toss has no effect on another, you can not make any assumptions about the color of a hat you don't see, based on those you do.
Since at least one player must guess correctly, and no players can guess incorrectly, you have to guess a sequence of 1-3 random binary (red or blue) variables. The chance of guessing right a sequence of length N is (1/2) ^ N, which decreases as N goes up. Therefore, the maximum chance is obtained by only one player guessing.
I can find no tricks in the wording, either, to point to a 'sneaky' solution, and the sentence 'The same game can be played....' really seems to state that there isn't.
Good work on those other riddles, though! The splitting of sock pairs solution was excellent!
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Tue May 28, 2002 2:34 pm |
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Michael C
Black Dragon
Joined: 09 Jul 2001
Posts: 1595
Location: Aarhus, Denmark |
Maggot: You are probably right, I came to same solution! But don't this solution bother you, it's just a confirming of a solution already suggested by the riddle teller!?? |
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Wed May 29, 2002 8:53 am |
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Lintra
Elf Friend
Joined: 23 Apr 2002
Posts: 9448
Location: Bermuda, the triangle place with SANDY BEACHES |
I thought I'd 'bounce' this thread ... it was a ton of fun.
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Thu Jul 07, 2005 11:50 am |
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Toaster
Bread Alert
Joined: 27 Jan 2003
Posts: 5475
Location: Sweden |
I've read through this thread, and the riddles, and it's real interesting. 
About the hat problem, take a look at this page: Click me! Now! Not very simple. 
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Thu Jul 07, 2005 9:01 pm |
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